Copying Numbers To CSV File Truncating Digits
Jun 16, 2008
I have a macro that copies long decimals (11 places) from an Excel file to a CSV file. However, the long decimals often get truncated from 11 places down to 3 or 4. I've tried a number of different coding methods to combat this, the most recent and most successful of which is shown below
Application.Workbooks.Open Filename:="C:...2008_alldata.csv"
Cells.Select
Selection.ClearContents
ActiveWindow.ActivateNext
Application.Goto Reference:="AllDataTable"
Selection.Copy
ActiveWindow.ActivateNext
Application.Goto Reference:="R1C1"
Selection.PasteSpecial Paste:=xlPasteValues
Range("R2:BI5000").Select
Selection.NumberFormat = "#,##0.00000000000"
ActiveWorkbook.Save
ActiveWindow.Close savechanges:=False
However, sometimes this method also fails. Is there a better way anyone knows of to ensure that the entire decimal is copied?
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Dec 5, 2008
I am using the code below to export my data to a new workbook, it creates a new workbook and copies the data into it except not all of it, strangely it seems to truncate the text from some cells ..
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Jan 27, 2014
We have had a few instances where Excel 2013 is truncating a filename when saving for example "MF Not Settled - Dec 13 Rental A.." the filename includes additional characters than this but has replaced them with .., I initially thought it could be a file path length issue but the files in question the total length is less than 150 characters including the server name.
This is also happening with links inside excel files to different tabs in the same workbook and well as macro names causing them to have to be ran manually as it has truncated the name to .. at the end.
find some examples below:
Full filename: MF Jan 2014 vols Smart churn sensitivity
Truncated filename: MF Jan 2014 vols Smart churn...
Also if you try to link to the truncated workbook whilst open it displays the formula as:
='[MF Jan 2014 vols Smart churn...sitivity.xlsm]Input c!$E$13
My work around is to save the file to another folder, without closing it, and then it works fine. However, in doing this it will try to save as the truncated name, so I first have to select the correct name of the file in the existing folder, before saving to a separate folder. However, if the file is closed, and then reopened the problem returns.
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Apr 30, 2014
I have the following working great, but would like to see it refine a little, as the data vlookup is 6 digits, but i only needs the last 4 digits is enough for me to work, my question is how do i go about adding that to the following function i have implemented and working fine.
=IF(ISERROR(VLOOKUP(B4,' cmfs01home$peter[tracker data 4-25-14-a.xlsx]ControlSheet'!$B$2:$F$301,4,FALSE)),"",VLOOKUP(B4,' cmfs01home$peter[tracker data 4-25-14-a.xlsx]ControlSheet'!$B$2:$F$301,4,FALSE)
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Jun 6, 2007
I want to import a excel file in the current sheet but want that few of the starting lines are not imported. Suppose i have a file with 500 rows but i dont want to import starting 39 rows.
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Aug 18, 2014
I found a formula that would copy only the last 2 digits of a previous cell and put it in a new cell. For example below, I want the cells to the right of the below to be:
12345 45
26548 48
21854 54
211ae ae
I thought it was a =right or something.
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Jan 29, 2014
I have a excel file, I need to remove the first two digits if they are certain numbers, such as 12. For example, if the number is 12987654, then I need remove 12, and it will be "987654" , but if it is not 12 in the first two digits, then keep it no change, for example if it is 345678, then keep it.
I barely work with Excel formulas, now I need connect the excel file with my Database table. I need to make the file matches the DB.
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Nov 17, 2009
Example numbers:
21130 & 21065
I want to check each number if EITHER of the two conditions is true:
1. if the third digit from the right (the hundreth place) is greater than zero;
or
2. if the second digit from the right (the tens place) is >=6.
If either is true I want to add a particular number to the original number.
My example numbers meet questions 1 & 2, respectively.
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Feb 2, 2010
this may be simple but I need to convent say
A1 = 09
B1 = 23
into
C1 = 0
D1 = 9
E1 = 2
F1 = 3
..etc
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Oct 13, 2007
I have a unique 6 digit number in a column. I have 2500 rows. I need to cut the first three numbers only leaving the last 3 numbers in the column for each row.
Example:
112345
234325
I would need 112, and 234 deleted. Checked the forum and cannot get quite what I want.
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May 6, 2008
I have a column with numbers in about 500 rows. The entries are 5 numbers long and others 8. So I thought i could use one of the following: A macro code to tell a cell to delete the first 3 numbers if the entry is 8 numbers long?
OR
A macro code to tell a cell to reduce itself to 5 digits long starting from the right? Attached is a small example
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Oct 15, 2013
I need to list 4 digit numbers in each section followed by commas, but whatever I do it goes to 3digits (e.g. I need "1234,5678,9123" and as soon as I hit Enter it goes to "123,456,789,123"). It wont work to format as text because I have a whole bunch of 12 digit numbers to break up into 4.
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Jul 16, 2008
I need a way to display all 8 digit numbers that have the digits 1-8 in them. (ie. 12345678 but NOT 12345679 OR 12345677) Also If I could somehow divide by 13 then check for whole numbers
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May 27, 2008
I would like to extract numbers based on the first 2 digits (22....) of a column along with its next column (on the right) and put them on another sheet.
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Nov 7, 2008
I am inserting data into my spreadsheet using VBA code to read a file and insert the data into the relevant cells. My problem arises when I have a string such as 80830410205724044. The actual code that inserts the data is as shown (temp is dimmed as string)....
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Mar 24, 2009
I have a UPC list. Some are more than 12 digits, and some with less than 12 digits. I need to make sure there are 12 digits in each UPC. I know how to count using LEN, strip leading zeros of those UPCs that are >12 digits using RIGHT.
What I need now is any number with less than 12 digits, such as 000123, add a 4 to the beginning (4000123) and fill in '0's in between the 4 and the short UPC number to make 12 digits, 400000000123. They vary from 1 to 13 digits.
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Jun 27, 2009
I have some numbers around 200 numbers which are not same digits i.e. if 1st number is 7 digits, 2nd number is of 10 digits.
Like this even if i have a number of 1 or 2 digits then all number should have equal digits i.e. in 200 numbers if one numbers is of 13 digits then all the numbers should be 13 digits.
To do this first i am doing this to the right align & comparison all numbers & taking the highest digit number & pre-fixing the other numbers with zeros so that all number are equal in number of digits. This is taking huge time.
I want to make a macro or any easy method so that all should have equal no of digits.
I want that if 200 numbers are pasted in the column E i.e. from E2 to E201 then all should be converted to equal digits number by prefixing zeros & should appear in column G from G2 to G201.
And after converting them it should be prefixed with D/ OR D/ABC:
This will be present in B2 cell i.e. this cell will be blank always. And once I have any thing in that cell that should be prefixed to the converted numbers in the column G & they should appear in Column I.
And again the numbers in column G should be prefixed with the content in B2 & should appear in column K in the Ascending order sorted.
Suppose if , I have 500 numbers then they should be converted automatically to equal digits & appear in Column G & prefixed with the contented in cell B2 should appear in Column I & sorted series in ascending order with prefixed with cell B2 in the column K.
And if I have 15 numbers only then it should do the same job easily. Here the numbers of numbers are not defined.
All this should be get done on click of the command button.
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Jul 16, 2009
I am trying to filter my excel sheet based on certain digits in a column of part numbers. The part number has 10 characters. I would like to filter it so that all part numbers where the 4th character is the number 5 or 7 is listed and where the 5th character is a zero. (i.e. R4X5831310 is a part number where 5 is the 4th character; I would like the filter to show this part number)
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Jun 1, 2012
vb code that will break out each 6 digit media used in their own rows such as in the illustration below.
Sample data before macro
Master Backup
GTI - Hostname
[Code]....
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Jun 22, 2014
I have a column that has section numbers like 001.002.006.003.010.011.002.
I would like to divide that single column into seven columns with only the single or double digit in it, ie
1 in a cell
2 in a cell
6 in a cell
3 in a cell
10 in a cell
11 in a cell
2 in a cell
Have been using MID and FIND togther, but when I get to the double digits like 10 an 11 I run into problems.
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Jun 17, 2009
I need a formula to drag down the attached that will place zeros infront of any numbers that don't have 9 digits. so if a part number consists of 6 digits then i need 3 zeros in front of it, if a part number consists of 9 digits then i dont need any zeros proceeding it.
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Nov 24, 2009
I have an excel template that needs to be copied multiple times and each sheet needs be named according to a list in an excel spread sheet. I also have a formula in the template that needs the value copied instead of the formula.
I got this script from an site and tried it. It runs but I don't see any spread sheets.
strComputer = "."
Set objWMIService = GetObject ("winmgmts:\" & strComputer & "
ootcimv2")
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Oct 31, 2008
i need to format my numbers in the following format
10,00,000.00
the first three digits will be separated and then subsequently 2 digits
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May 21, 2009
I have an address file containing a few hundered thousand rows of data. The max character lines for my lables is 60 and unfortunatly a large number of the fields exceed this limit. I need to create a string somthing to the effect of:
delimination
if len(A2<60) end
if len(A2>60) then
if character 60 isblank then deliminate = 60
if character 60 not isblank then deliminate at blank < 60
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Jun 11, 2009
I form a string and put that string into a selected cell as a comment. Mostly it works fine but as the string gets over a certain length (255 characters?), the string gets "truncated" in that only the characters over that length get put into the comment.
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Mar 8, 2007
Someone gave me a spread sheet that lists o-ring sizes. Each field has a measurement followed by a +/- range. I need to split the +/- range out into a seperate field. The full sheet has over 400 rows of data. Is there an easy way to automate this? I attached a sample of the sheet.
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Mar 15, 2009
I have a spreadsheet with 4 columns of information, then a column for a primary name, and then many columns of secondary names (with a different number of secondary names for each row).
For rows with more than 1 secondary name, I need to create a new row with a copy of all the columns up to the secondary name for each secondary name in the row.
A row in the spreadsheet looks like this:
data data data data PrimaryName SecondaryName1 SecondaryName2 SecondaryName3... SecondaryNameN
I need this row to be replaced by the following set of rows:
data data data data PrimaryName SecondaryName1
data data data data PrimaryName SecondaryName2
data data data data PrimaryName SecondaryName3
...
data data data data PrimaryName SecondaryNameN
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May 17, 2007
I am trying to plot data that I have read out of a PLC (via csv file) . The date/time data shows up as follows: 2007-05-14T02:15:00.020-07:00
In this example, the suffix .020-07:00 is extra information and causes problems with graphing the info. Also, the cell is a not a number value, and I can not force it to be a general, number format.
I would like to truncate the cell or extract the time out of it such that I can plot the PLC data in a meaningful "parameter vs time" graph.
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Sep 25, 2009
I am editing a wine database which contains a vast amount of data, one column has the wine name and sometimes the vintage year in the begining or at the end of the cell. Sometimes the year is made of 2 digits (03, 05, ..) or 4 digits (1978, 2004, 2005, ...).
Is there a way to remove this vintage year form the string?
to make matters worse, there is often a single quote/apostrophe in front of the vintage year, which is driving me mad as 98% of the time it is one of these hidden ones that cannot be deleted using the find/replace function.
examples are like below:
De Wetshof Finesse/Lesca Cahrdonnay 07
De Wetshof Sauvignon Blanc 07
Lord Neethling Cabernet Franc 2002
Lord Neethling Pinotage 01
Bouchard Finlayson Tete de Cuvee Pinot Noir 07
Jacobsdal Pinotage 1994
Zondernaam Sauvignon Blanc 2007
Tokara Red
1976 St Emilion
03 Tokara rose
Plasir de Merle Cabernet Sauvignon 05
DuToitskloof Pinotage/Merlot/Ruby Cabernet
1999 Tradition Juracon 375ml
I have been searching the Internet for the past 2 days without luck on how to delete the end of string vintage year.
I have had some luck with the left side, as in:
=IF(ISERROR(VALUE(LEFT(B2,SEARCH(" ",B2)-1))),B2,MID(B2,SEARCH(" ",B2)+1,LEN(B2)))
As I am not an expert with Excel, I have no idea on how to use VBA (every time I have tried even basic things, I failed) nor even sure how the above funtion works (found it on another site).
I thought I could acheive my goal in two steps, first removing the left side vintage and use this partial result with the RIGHT equivalent funtion, but it simply is not working!
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Sep 25, 2009
I am editing a wine database which contains a vast amount of data, one column has the wine name and sometimes the vintage year in the begining or at the end of the cell.
Sometimes the year is made of 2 digits (03, 05, ..) or 4 digits (1978, 2004, 2005, ...).
Is there a way to remove this vintage year form the string?
to make matters worse, there is often a single quote/apostrophe in front of the vintage year, which is driving me mad as 98% of the time it is one of these hidden ones that cannot be deleted using the find/replace function.
examples are like below:
De Wetshof Finesse/Lesca Cahrdonnay 07
De Wetshof Sauvignon Blanc 07
Lord Neethling Cabernet Franc 2002
Lord Neethling Pinotage 01
Bouchard Finlayson Tete de Cuvee Pinot Noir 07
Jacobsdal Pinotage 1994
Zondernaam Sauvignon Blanc 2007
2003 Tokara Red
1976 St Emilion
03 Tokara rose
Plasir de Merle Cabernet Sauvignon 05
I have been searching the Internet for the past 2 days without luck on how to delete the end of string vintage year.
I have had some luck with the left side, as in:
=IF(ISERROR(VALUE(LEFT(B2,SEARCH(" ",B2)-1))),B2,MID(B2,SEARCH(" ",B2)+1,LEN(B2)))
As I am not an expert with Excel, I have no idea on how to use VBA (every time I have tried even basic things, I failed) nor even sure how the above funtion works (found it on another site).
I thought I could acheive my goal in two steps, first removing the left side vintage and use this partial result with the RIGHT equivalent funtion, but it simply is not working!
Does anyone have an idea on how to help with this?
Ideally I would love to cut the vintage year, whether 2 or 4 digit, whether on right or left of cell and paste it in another cell, so to avoid manually doing it.
However, this is surely too complicated to do, so iwould settle with just deleting the vintage year and manually typing the vintage in another cell.
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