# Subtracting Time (in Numbers) To Decimal

Oct 21, 2009How can I add/subtract time entered as 1830 to give a decimal value?

Start=1830

Finish=2000

Time between = 1.5

Also, how can I convert time as 1830 (24hr) to 12hr time? ie. 0630.

How can I add/subtract time entered as 1830 to give a decimal value?

Start=1830

Finish=2000

Time between = 1.5

Also, how can I convert time as 1830 (24hr) to 12hr time? ie. 0630.

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How to convert decimal numbers which represent minutes into time format? Like this

Sheet3 GH1MinutesTime212.9729729700:13:00325.9459459500:26:004116.756756801:57:00

Any way to enter in a total amount of time and then subtract it from a time shown. So for example:

I want to enter in a time of 26 hours, 10 minutes and 2 seconds: 72:10:02

I cannot find a format that allows me to enter the hours in excess of 24

Then I want to subtract it from a time of the day which will be entered as AM/PM: 02:40:02 AM

Then I want to show the result as a time of day: 00:30:00 AM

Lastly, I want to also show the amount of days adjustment: -1d, 00:03:00 AM

How this can be done through cell formulas?

I have three cells... A1= entry time & H1 exit time...both are formated as such Custom #0":"00 so i don't have to enter the colon with every entry and exit time... my issue is that i want the third cell to count the minutes in cell A1 & H1...

View 9 Replies View RelatedI saw this answered somewhere on here but really didn't understand.

I'm trying to set up a sheet for my hours worked for the week.

I have the total per day in H2 through H6 In I2 through I6 I have an accumulative total for the days, so assuming I work 8 hours a day, I2 would be 8:00 I3 would be 16:00 I4 would be 24:00.

In J2 through J5, I'd like to have the weekly accululative worked hours subtracted from 40 so that the total is what I have left work until I hit 40.

Here's a simple one guys. How do I subtract 7:30 AM from 4:00 PM to give me 8.5 hours? At the moment it returns either 8:30 AM or (formatted Number - General):

0.3541667

I need 15 minutes removed from a difference in time, if the time span falls over 9:00 am through 9:15 am.

I'm inputting time like 8:30:00 in A1 and 10:30:00 in A2, then calculating the difference in A3 (2:00:00). Is there a way to remove 15 minutes from that 2:00:00, since it falls over 9 to 9:15?

I am trying to subtract 45min from the time 00:05, but the result i am getting is 0:40 which is wrong.

I am using below formula.

=TEXT(ABS(B3-$A$3),"-h:mm")

Actual timeTime minusResults00:0500:45-0:40

I am trying to work out the response times to an event that my staff attend ( such as a fire alarm)

In C1 will be the time the event was called in, 23:55

In E1 will be the arrival time, 23:59

In F1 I want to show the time taken to arrive on site (response time)

This seems straightforward until the arrival time goes into the next day, such as 00:05 and this is when I have the problem

To make it more complicated, sometimes there is no need for an arrival time to be entered for some events ,with the end user leaving it blank or putting "NA" or "na" etc into the cell

I have tried the below formula which works to a point but leave me with an ######### error if the time is after midnight

=IF(E1="NA",0,IF(E1="n/a",0,E1-C1))

I have the formula in my spreadsheet to compute time. It works only if the time in B1 is greater then the time in A1. I would to know if there is a formula to compute time with either negative or postive answer. For example if a carrier was set to load their papers at 12:02pm and ended up loading early at 11:50am I would like the result in C1 to be -12 or (12).

Currently I am using the formula: =HOUR(B1-A1)*6+MINUTE(B1-A1). Like I said, it is all good until someone loads early and then I get a "#NUM!"

Are there any other formula's that I can use or is there a simple modification to the formula I am using?

I have some intraday date that looks like this, hope the formatting comes thru when i post this....anyhow, the second column is TIME (ie 15:25 15:30, etc...5 minute time intervals for SP500 stock data. I want to have a column that simply subtracts row 2 column b (time column) from row 1 column b.....when i do this i get a #value....I know this must be possible to get a result i need....ie 15:30 - 15:25 = 5

Do i need to reformat the TIME column into something different? ....

I'm trying to program a spreadsheet for staff attendance at a school. In the spreadsheet the staff member has personal days, sick time, and sick time in the bank (sick time rolled over from last year). When they use sick time, it needs to come out of the bank first, until it reaches zero, then it should move on to the sick time accumulated for this year.

Staff attendance WIP.xlsx

On the left side is the staff name, sick time, personal days, and bank. Then are the school days for July (if a staff member uses sick time/personal day it is placed under the date it was used). On the far right is the total remaining amount that the staff member has left.

The formula I have for cell AF4 is: =MAX(0,G4-SUM(H4:AC4)) so that the cell will not go below zero.

The formula I have for cell AG4 is: =E4-(COUNTIF(H4:AC4,"P")+(COUNTIF(H4:AC4,"HP")/2)) So that when P for personal day is entered, it will take a whole day, and when HP is entered a half a personal day is subtracted.

I need to figure out a formula for cell AD4. I've tried a couple of formulas I've seen on other posts, but they weren't for a series of numbers like this. And when I put them into this particular spreadsheet, it would subtract the bank until zero, move on to the 'sick time' cell and subtract the SUM of all the days sick rather than subtracting what was left when the 'Bank' reached zero.

In cell L7 I have (80/60)/24 and formatted h:mm to get 1:20. In cell M11 I have 1:00 (h:mm). In cell M12 I have L7-M11 and get the result 0:19. Why I'm losing a minute and not getting the result 0:20?

View 5 Replies View RelatedI have a working week that starts at 07:00 on a Monday morning and finishes at 14:30 on a Friday afternoon.

For planning purposes I need to know at any given point how many working hours are left. The reason for this is so that I can multiply that figure by the amount of Engineers available which will give me the amount of Man Hrs left in the week.

For example - if it is 11:00am on the Tuesday, how many working hours are left ....

I've tried a number of examples but I can't seem to get it to work. the desired results in column C.

10/17/11 12:00 PM10/17/11 1:00 PM1:0010/17/11 12:00 PM10/17/11 9:00 AM(3:00)10/17/11 12:00 PM10/16/11 9:00 AM(27:00)

I am having trouble finding the difference between times. I have two cells, A1, A2. Times will be placed in there each day. A1 will have the first time and A2 will have a later time that day. i.e. A1 12:25AM, A2 2:45AM. A3 would have the formula. In this case I am looking for an answer of 2:00 (2hrs).

My second issue will be times when I have A1 11:20pm and A2 1:20am. I can't seem to get it to work.

My challenge is discovering the difference in time between two rows of data that is imported with milliseconds in the time slot. In my example below I would like to see how I can subtract the time listed in line 4 from line 3 (11:18:59.566 - 11:18:59.550). When I try now I get either 1.85185E-07 or 00:00.0 or 0.000000 depending how the cell is formatted.

2012 02 17 11:18:59.050|081,999999999999~999999999999

2012 02 17 11:18:59.550|082,MCTO05222CZ0~999999999999

2012 02 17 11:18:59.566|082,1

2012 02 17 11:19:00.144|083,MCTO05246CK0~999999999999

2012 02 17 11:19:00.160|083,3

I am trying to subtract 12 business hours from a date/time stamp. It has to be during working hours however which are 8AM - 5PM, Monday-Friday.

For example if my value is 6/23/2008 9AM

Subtracting 12 business hours would give me 6/19/2008 3PM.

formula to work out a variance between two times

Using the 24hr time format in cell a1 i have a start time of 10:43 and in cell b1

i have an estimated time i think a job should take in this case 30 minutes and in cell c1 i have the actual time that job was finished in this case 11:07 and in cell d1 i have a variance between the two times which in this case would be saving me 6 minutes

I need to convert regular time to decimal time. example regular time in A1

is 1:38 I need that number to be converted to decimal time = to 13:63. add

12 to the hour and divide 38 into 60 to get the minutes. Our time clock

prints on a 12 hour basis and I enter to excel in decimal time.

I've got a time difference from 8:00AM - 12:30PM as 4.30 I'm trying to get the minutes, .30, converted into a 6 minute increment, .5. Is it possible to do this and if so how would it be done? Below is a chart of how the time is converted from 6 minutes increments into decimal form.

6 = 0.1 36 = 0.6

12 = 0.2 42 = 0.7

18 = 0.3 48 = 0.8

24 = 0.4 54 = 0.9

30 = 0.5 60 = 1.0

I need to separate a list of times from a telecommunications bill. I have 170,000 line of data.

The Times are represented as below.

eg

46 46 Sec

59 59 Sec

100 1 Min

159 1 min 59 sec

200 2 mins

502 5 mins 2 sec

1256 12 mins 56 sec

3456 34 min 56 sec.

How do I separate them to a decimalized per min value.

we work with both Lotus 123 and Excel 2003. Lotus will be gone next year, but for now, the official mean to publish our reports is Lotus. With my work, I copy/paste a Lotus page to Excel. I use the following macro to convert Lotus format numbers (which Excel considers as text) to real numbers:

Sub ForceToNumber()

Dim wSheet As Worksheet

For Each wSheet In Worksheets

With wSheet

. Range("IV65536") = vbNullString

.Range("IV65536").Copy

.UsedRange.PasteSpecial xlPasteValues, xlPasteSpecialOperationAdd

End With

Next wSheet

End Sub

Source : http://www.ozgrid.com/forum/showthre...087#post184087. The problem is that I need to send back this data in Lotus. Excel considers decimal numbers with a coma as real numbers and numbers with a dot as a text. This previous macro fixes that. However, Lotus works the other way. Only numbers with a dot are considered real numbers. So I would need to find a way to code a macro that converts any numbers in the Excel sheet to a number with a dot. It's a bit like doing the opposite operation.

How do you convert decimal time to standard time?

....Hrs

A1 21.70

A2 7.20

A3 37.38

I know 1.5 is 1:30 but I don't know the formula.

From a list of numbers I would like to delete values that have cents so only those transactions with a .00 amount are displayed

For example

34.95

21.88

21.00

56.00

45.77

Only those valaues ending in .00 will list. I tried filtering but I think there most be a function(s) string that might work or at least filter out the values with cents

I'm trying to make a shift schedule template, and it's all done except that i cant sum the hours the way I think i should be able to.

I've attached the file for reference.

I've added in some hours for myself as an example. I have 47.5 hours in the week. I've got 3 Rows, In Out and Hours. I've formatted the In and Out the way i want them, but I would like the Hours row formatted as a decimal, so that 7 hours 30 minutes would show up as 7.5.

I'm also having trouble with the totals column at the end. Although D8:J8 total 47.5 hours, it's adding them as 23:30.

Data from a SQL database represents time of day as a string of x's when imported into Excel. With CLEAN, I found that noon is -0.5.

This means that the calculation being used for noon is (24 * -0.5), or -12, meaning "go to the end of the 24 hour day, then go back half a day to noon." Similar calculations work other times of day.

Time entries that start in one day and end in the next are not allowed, so there is no problem with a change in day,

How can I convert this to the AM/PM time that my users need?

I am trying to convert time (formated as hh:mm) to a number with 2 decimal places.

Example

A1 7:51

B1 - want the number to show 7.85

Will then multiply this by an hourly wage to get total $ paid.

Is there a way to delete only numbers ending in a decimal from a column of numbers? I have a column of numbers but only the non decimals are relevant to the next equation.

View 3 Replies View RelatedI am trying to find a way of counting decimal numbers if, say, they begin with 3.

For example, I might have 3.33, 4.1, 3.0, 5.65, 3.8, 3.7, 3.33, etc.

I want to count anything that begins with 3 (3.33, 3.0, etc). Using the data above the answer would be 5 ...5 numbers that begin with a 3.

If this possible?

There doesn't appear to be the facility with Countif. I don't want to truncate the data (the spreadsheet already is quite extensive). I have tried using =SUMPRODUCT((Y$2:Y$170 >=3)*(Y$2:Y$170<=3.9)) but this will return an answer only when there is a complete set of data within cells within the range.

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