Listbox Returns Same Listindex For Duplicate Bound Column
Oct 11, 2006
I have a listbox on a form that refers to a dynamic range. The problem I have is that the listindex returned from selecting an item in the listbox returns the same number for an entry of the same value in the first bound column (in this case Col A, see below). I guess it's kind of acting like a primary key if.
My Dynamic Range that shows up In the listbox.
Col A Col B
0700 1500 '<-- returns Listindex = 0
0700 1800 '<-- returns Listindex = 0
0800 1630 '<-- returns Listindex = 1
0800 1830 '<-- returns Listindex = 1
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Jun 28, 2013
I am looking to count group numbers that are bound to a nomenclature number. So I have made an example below. The nomenclature number is bound to 1. So I want to count all the 1's that are bound to 0912, which would be 5. and the same goes for 1234. the 2 is bound to the nomenclature 1234, so i want to count all the 2's that are bound to 1234. Which would be 3.
Group
nome
1
0912
1
1
2
2
2
1234
1
1
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May 14, 2014
Column A has values increasing by 1 but not necessarily each row, i.e.
1 1 1 2 2 2 3 3 3 4 4 4 4 5 5 5 5 7 7 7 8 8 9 10 10 11 11 11 11 12 13 13 14 14 14
I have a listbox which I want to Initialize by listing these values but not duplicating them (so in this case it would contain 1-14). Here is the mindblowingly complicated code I currently have:
[Code].....
This gives me the list as it appears on the sheet but doesn't get rid of the duplicates for me.
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Apr 4, 2014
im trying to create a two column listbox that will transfer both columns to the listbox on the right and also transfer from the right to left currently right to left works but when I trasnfer from the left to right then the right to left only one column is moved.
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Nov 5, 2008
For some reason my selection won't return to where it's supposed to in a listbox after I've increased it's column widths. It's very strange.
I've put together an example of the issue as the actual workbook is enormous, but the demonstration seems to work.
I've tried exporting the Listindex resetting code to an external function, but it didn't help either.
Can anyone understand this behaviour?
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Nov 18, 2008
I am working in excel 2003. I have a number of combo boxes, and I would like to get the listindex of a given box. It is easy to get the value of the box number "x"
Controls("Combobox" & x).value
works no problem, however
Controls("combobox" & x).listindex
does not work, and while I can do
Combobox1.listindex
I cannot figure out how to make the 1 a variable.
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Jul 27, 2006
I have a combobox which properly populates the list of items it should display, however upon selecting the item the combobox displays that item's listindex, not the cell contents. I've tried to populate the combobox a couple different ways and the list from which to choose displays properly all the time, but upon selecting I cant get it to stop displaying the listindex.
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May 1, 2007
I have a dateset that I am creating a userform for. The problem is my dataset has more than 32765 rows, usually around 35000. How can I work around getting the "overflow" error when my users click on a selection > the limit imposed on a listbox?
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Feb 26, 2008
I need some assistance with the code below. I have a userform that has a listbox with 2 columns of information. When there is a match between the value in the listbox and the value in the cell for a given row, that row is deleted. I thought this was very straightforward, but i'm not getting this to work right...
Private Sub cmdDelete_Click()
Dim Val2 As String
Dim Val3 As String
Dim doit As Long
Dim roww As Long
Dim LastRow As Long
Val2 = ListBox1.List(ListBox1.ListIndex, 0)
Val3 = ListBox1.List(ListBox1.ListIndex, 1)
doit = MsgBox("Confirm that you want to delete the entry", vbOKCancel)
If doit = vbOK Then
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Feb 1, 2010
I have a table with 3 columns. See below for data (ignore dashes):
COLUMN X-----COLUMN Y-----COLUMN Z
Project 1---------21 Dec 09---------$70
Project 2---------21 Dec 09---------$85
Project 3---------21 Dec 09---------$90
Project 1---------1 Jan 10-----------$85
Project 2---------1 Jan 10-----------$95
Project 3---------1 Jan 10-----------$110
As you can see, COLUMN X contains Project Names, COLUMN Y contains Dates and COLUMN Z contains Monetary Value.
Here is what I need to do: I need a formula/function that will lookup "Project 1" in COLUMN X and find the latest corresponding Date in COLUMN Y (for this example, 1 Jan 10) for Project 1 and then display the corresponding Monetary Value from COLUMN Z (for this example, $85).
I have tried using VLOOKUP, but since the data must be sorted it won't work. I tried using INDEX(MATCH), but can't get it to work. My goal is that the cell will be dynamically updated every time a user inputs updated data for a certain project based on the latest date.
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Sep 21, 2008
I need a dynamic formula in A1 that returns min value in column B in a range of the last input and 15 cells back.
Then I need another dynamic formula in B1 that returns max value in column B in the same range.
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May 3, 2013
I have a range from B20:Z520. I would like to copy the entire row B:Z if Z returns "1", with numerous rows having "1" To be specific, I would like it to be copied to N6 onwards. The active worksheet is named "Dashboard"
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Mar 27, 2014
Let's say I have data that looks like this grid below. Each color represents a column heading and each number is a data point within that column.
Blue Red Green Yellow
18 27 15 36
56 41 3 22
Can I write a formula that would do the following 2 things with the data in this format:
1. Find the max of the data...simple =Max(...) formula
2. Use the max to return the column heading. In this case the max is 56 so the value I want to return is "Blue"
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Oct 17, 2007
i have a column that is seperated by hard returns how can i seperate them into new columns.
can i find replace a hard return and then text to columns.
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Jan 30, 2013
I have three different values in three different columns and I want to find the maximum amongst the 3 values.
A1 B1 C1
100 50 40
in D1 I have written a formula
=MAX(A1, B1, C1)
But it is returning an error saying formula you typed contains an error
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Jan 16, 2014
I have a table (A1:C5)
A1:C1 contain the table headers
A2:C5 contain the data
A6 contains the value I want to search for I use this formula to return the column header of A6 A6=INDEX(A1:C1,SUMPRODUCT((A2:C5=A6)*COLUMN(A2:C5))) Now, if there are duplicate values in A2:C5, this will return more than one column header What I need is a vba code to view a msgbox with all column headers returned in this case
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Apr 19, 2008
I have a nice case to prepare and need weekly riskfree interest returns on the UK treasury bond. Right now I have daily returns and want to convert them into weekly. The problem is, weeks do not always contain five trading days. How can I turn my data into weekly average riskfree interest returns?
******** ******************** src="*********>*********>Microsoft Excel - UK interest daily.xls___Running: 11.0 : OS = Windows XP (F)ile (E)dit (V)iew (I)nsert (O)ptions (T)ools (D)ata (W)indow (H)elp (A)boutA1=ABCD1DateInterest rateweekday 24-Jan-889.871 35-Jan-889.992 46-Jan-8810.053 57-Jan-8810.094 68-Jan-8810.135 711-Jan-8810.051 812-Jan-8810.072 913-Jan-8810.283 1014-Jan-8810.114 1115-Jan-889.985 1218-Jan-889.871 1319-Jan-889.962 1420-Jan-889.913 1521-Jan-889.864 1622-Jan-889.715 1725-Jan-889.71 1826-Jan-889.762 1927-Jan-889.693 2028-Jan-889.564 2129-Jan-889.555 221-Feb-889.741 232-Feb-889.622 243-Feb-889.643 254-Feb-889.684 265-Feb-889.755 278-Feb-889.931 289-Feb-889.852 UK interest daily [HtmlMaker 2.42] To see the formula in the cells just click on the cells hyperlink or click the Name boxPLEASE DO NOT QUOTE THIS TABLE IMAGE ON SAME PAGE! OTHEWISE, ERROR OF JavaScript OCCUR.
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Feb 15, 2007
I need a formula to count cells based on the date, so that I can have a blank cell when the answer is 0. I am adding values cumulative and future cells need to be blank because I have a graph that has a trend line and I don't want the trend line to fall off at the end. I also don't want to have to go back to this every month and update it.
Column A
Date
1/2/2007 0:00
1/3/2007 0:00
1/10/2007 0:00
2/10/2007 0:00
2/10/2007 0:00
2/15/2007 0:00
3/22/2007 0:00
3/22/2007 0:00
3/22/2007 0:00
4/31/2007 0:00
4/31/2007 0:00
4/31/2007 0:00
Column B
Invoice #
CM-0003881
CM-0003882
CM-0003883
CM-0003888
CM-0003928
CM-0003932
CM-0003933
CM-0003985
CM-0004007
CM-0004008
CM-0004009
CM-0004065
I have this formula in cell F3 that will add the dates through the end of January:
=SUMPRODUCT((A1:A1000>=DATEVALUE("1/1/2007"))*(A1:A1000
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Dec 8, 2009
I have a sheet where i want to delete duplicate rows where column A and column B combined are equal, i.e. range(Ax:Bx) where x is the current row. I am using the macro below but cant seem to get it working as I keep getting a type mismatch error and Im not sure why.
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Aug 2, 2014
I have created a calculated column in PowerPivot and inserted a formula that worked in a normal excel spreadsheet however, this formula does not work in PP anymore.
=find("green",Table1[Name],1)
Name column:
NAME: Bag green
it should find "green" in the name and return the position. Hoever it alway returns the error, that the find function could not find the string.I have attached an example spreadsheet.
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Sep 11, 2012
I'm trying unsuccessfully to write a function that looks for a column in a pivot table and returns the entire column as a text string. The function should take a pivot table and a text string as an argument. The text string is the name of one of the columns. The function needs to return the entire column (excluding the header and footer rows) as an array.
In the example I pasted below, the function should take the pivot table (PivotTable1) and a color, say "Red", as arguments, and then return the values in the Red column as a 48x1 single vector array, in the order shown, starting with 43 and ending with 1. I can only post a text version of the spreadsheet; I was not able to post the actual spreadsheet.
Average of Cost
Color
Date
Hour
[Code]....
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Jul 18, 2014
Excel 2010: I'm working with a sheet where I would like to get accurate results on the make and model of cars sold in a given week. The workbook contains several worksheets each representing weekly sales numbers for different vehicles.
The Make-Models tab has the lists used to create the drop-down selections.
The Sales tab allows one to create an ad hoc report on the total number of vehicles sold, by Make and Model. Cell B2 is named 'SelectedModel' and used in the formula found in column E, Total Sold.
Problem: When I select Honda, for example in B2 of the Sales worksheet then select Accord in cell B3 of the same. The results returned in E2, E3 and E4 are 2, 3 and 4, respectively, instead of 8, 3 and 7.
2 Honda Accords were sold on Monday and 6 on Tuesday of the same week. My formula is only returning the first matched value of 2 whereas I would like it to return 2+6, 8 for week 1. Same goes for other weeks.
Select any other make and model and notice the problem follows. I believe the error is due to incorrect usage of the formula or incorrect formula altogether.
IF(ISNA(INDEX(Week1!E:E,MATCH(SelectedModel,Week1!B:B,0))),0,
INDEX(Week1!E:E,MATCH(SelectedModel,Week1!B:B,0)))
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May 26, 2006
In my current worksheet, IF(0 = "CS") returns TRUE, but on any other file this same argument returns FALSE. The cells' formats are both general. I want it to be FALSE.
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Mar 5, 2014
I am having trouble with my macro. I have attached excel sheet for reference.
Basically, I want a Macro that Looks up columns B & C of current sheet and matches it with table in the charges tab, and then returns hourly pay in column D.
I have created the macro but it's giving me Run time 1004 error.
Also, my formula is incorrect. Maybe that's why my macro isn't working?
2WayLookup_Macro.xlsm
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Feb 8, 2008
I am trying to set up a listbox on a userform that will draw from 2 columns. The first column is an abbreviation of the phrase in the second column as shown below. When the user clicks the listbox arrow I want them to see the descriptor of the 1 - 3 character code since they are not always intuitive. When the selection is made I want the form to capture only the code.
IP In Progress
AMAwaiting Materials
ADAwaiting Design
CPCompleted.
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Dec 4, 2013
This is my code:
VB:
Set R = WS3.Range("A:A").SpecialCells(xlCellTypeConstants)
ListBox1.Clear
With ListBox1
[Code].....
the third column is a time, and is showing up in the actualy listbox as a decimal rather than a time. How do you show at time(ex 12:42 PM)?
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Nov 26, 2004
I have a Listbox that has 2 columns
Using Additem how do I place data in the 1st then the 2nd column to create a list.
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Apr 7, 2014
i have a listbox1 with range A61:AG500
33 column
i don't want to show some column in listbox1 e.g F, G, J, K O, W, X .......
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Jul 22, 2014
I have a four column listbox where 4th column is percentage. In my source worksheet cells are formatted as percentage but when this is displayed in list box it shows approximately 10 decimals or maybe even more. How can I change my code only to show two decimals in 4th column?
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Jan 12, 2010
I am not grasping how to setup a multi column listbox (2 columns).
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