Loop Macro To Check If Cells Not Empty

Jun 27, 2014

Column 'N' and 'O' will be used for inputting information and will never be hidden

Column 'E' through 'F' hold information, however the user will have hidden all but one of columns 'E' through 'F' before running macro

Once the user initiates the macro, the program will detect which column in 'E' through 'F' is not hidden

The macro will then start at row one of the unhidden column and loop down looking for the text 'Req' (not including ' )

If the loop finds 'Req' it will search in column 'N' of the same row for any data at all
If it finds data in column 'N' for that particular row, it will check column 'O' of that same row for any data at all
If it finds data in column 'O' also, then all 3 parameters have been met

The loop should continue checking for these 3 items through row 500

If the loop determines that for every 'Req' found in the unhidden row there is data in the corresponding column 'N' and 'O' a message will appear that says 'Checklist Complete"

Upon closing the message box, the file should save and then exit

If the loop determines that for every 'Req' found in the unhidden row, there is not always data present in column 'N' and 'O' the message box should appear and say 'Checklist Incomplete'

In the same message box, it should provide a list under 'Checklist Incomplete' that provides the text found in column 'D' for each row where it failed the test of having 'Req' in the unhidden row and data at all in column 'N' and 'O'

That last part will give the user a tool to see where they might have forgotton to enter data.

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I have data in Row 53 that spans 7 columns, but stays in the same row. I want to design a loop to select every 7th cell in that row and check if it is empty. If not, add onto a "counter" then display the final number of occupied cells (the value of the counter) at the end. This is what I have so far, but I get all sorts of errors.

Code:
Sub Tester()

Dim WB As Workbook
Dim WS As Worksheets
Dim modCounter As Long
Dim Cell As Range

Set WB = Workbook("Transverse Series.xlsm")
Set WS = WB.Sheets(BM18)

[Code] ......

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y = 1
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The problem I am having is getting it to loop through the sheet and bring back the right results. It is only matching on row 2 of the database sheet when I select cabbage in the vegetable combo box and apples in the fruit combo box . I cannot figure out how to get it to loop through all the rows for the range I want to compare (A2:G7) - I need this range to be flexible so as data is added it will expand to read all added rows.

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I attached the spreadsheet and I am explaining what I want to do and the expected result.

Fruit
Fruit Type
Vegetable
Games
Toys
Cereal
Ball

[Code] .....

What I want to do is loop through the Database sheet and if the fields on the form contain all the values in any row of the Database sheet, excluding empty cells in the Database sheet, then display a message.

So if on the form I selected Broccoli fron the vegetable combo box, Cricket from the games combo box, puzzles from the toy combo box, bananna from the fruit combo box, grits from the cereal combobox, and baseball from the ball combo box, in the databse sheet tabel shown above the match would be row 6 since the values for vegetable, game, toy, fruit, cereal and ball on the form matches what is on row 6 of the Database sheet. It does not matter what other fieds are selected /filled in on the form, the match should only take into consideration the populated cell in each row of the database sheet.

So, if the user enters Apples in the fruit combo box and Cabbage in the vegetable combo box but had blank or something other than bike in the toy combo box on form it would be a match to the Database sheet row 2, regardless of what the user enters in the remaining fields on the form

If the user enters Berries in the fruit combo box, Blueberry in the Fruit Type Combo box, Carrot in the vegetable combo box, and Grits in the cereal combo box it would be a match to Database sheet row 3, regardless of what the user enters in the remaining field on the form .

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