Bypassing Reference Error

Jun 2, 2014

I am creating a worksheet that needs to input information from other worksheets that have not been created yet. I will be using this to input information as time goes on (monthly); however when trying to create the cell, I get a message that says "a formula in this worksheet involves one or more invalid references. Verify that your formula contains a valid path, workbook, range name, and cell reference." The worksheets I am trying to reference will be created eventually, but I want a formula that will not have to be updated monthly and I can just use it to roll over month to month.

My current formula looks as such:
=IF((IF($A$2=1, '[2014 Corp Engineering Project Codes.xls]Period 1'!$A13, 0))
(IF($A$2=2, '[2014 Corp Engineering Project Codes.xls]Period 2'!$A13, 0))
(IF($A$2=3, '[2014 Corp Engineering Project Codes.xls]Period 3'!$A13, 0))

[Code] ........

I have up to 'Period 6' created so far, the error highlights 'Period 7'.

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I'm attempting to SUM a column of data (5 cells). It's possible that I will have #N/A in any number of them, as they call their data from another cell. Specifically, if C16 is:

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This becomes an issue when a billing plan isn't selected in B16, and returns #N/A for C16. For formatting and cleanliness, I have conditional formatting on C16 that states =ISNA(C16) and changes the font color to white.

WE'RE STILL NOT TO MY PROBLEM!

I can deal with the #N/A in C16-C20 with conditional formatting. What I can't deal with is my billable minutes total cell (E50).

The cell should add the billable minutes in C16-C20, but doesn't. I believe it's because the information in C16-C20 is actually text, returned by the index, and not a true number. Is there a way around this or should I change my method in some way?

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Function LastRow(sh As Worksheet)
On Error Resume Next
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The code

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I can click on the cells and press F2 once then F4 three times to get the formula over to the desired non-fixed format, however, I have to do this for 12 different workbooks and on roughly 40 columns for each.

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This formula might be the problem for the error message.

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Code below.

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'
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'
'
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[Code] .......

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