Copy Every Second Column Header And String Something On
Mar 12, 2009
I have this spreadsheet, I have a title in cell A1, then the following column headers alternate betweens entries I want and those I don't (in this case A in Cell B1, an irrelevant value in C1, C in Cell D1, an irrelevant value in E1, D in Cell F1 etc...).
What I want to do is take the original value, so A from B1 and make it Aa, then make C1 contain the same A, but this time Ab.
It should be very obvious what I'm after from the spreadsheet.
I am a macro newbie and I think this is beyond me.
I've been trying all morning with no success to make a macro that will copy data from all columns of one workbook containing specified header text to a single column in a different workbook.
So for example, I've got a workbook called coupon barcodes that has multiple tabs for each person redeeming coupons on sheets 2-88 (sheet one can be skipped) and some of the columns are labeled "voucher 1" in cell A4 or B4 or C4 etc. with a list of all the coupon barcodes that customer redeemed below that. I want all of the data from all of the columns in this workbook that have the header "voucher 1" to be copied and pasted into one column (order doesn't matter) also labeled "voucher 1" in another workbook I have open called vouchering database.
There must be a way to do this that is easier than searching the internet all afternoon again
I have a spreadsheet and I was wondering if there is a way to copy from a specific range in say A1:A5 in Sheet1 and paste into Sheet2 where the column matches cell A1 in Sheet1.
I am trying to do this in VBA and I was wondering if there is a way to do this.
I have a workbook with many sheets of similar but not identical data. I need to extract columns from each sheet based on 5 header criteria and paste them to a single sheet. Each worksheet contains these 5 criteria.
I've been working with the VBA script I've pasted below. It's grabbing the 5 column criteria that I have in sheet 12, and comparing them to sheet 1 in the workbook, then copying them to sheet 12. This much is good, but I need the script to also return the data from the other worksheets as well. I've tried modifying the script based on other loop functions in other scripts I've found, but I'm not having any luck.
I've been trying find an appropriate formula to extract the column header from a table in a different sheet if the row header and value in that table is known.
in the lookup table the row titles (column A) are product codes, column titles (row 2, D through AX) are business names and the table values are quantity.
In a different table I have product codes in column A and in column B i have the max number/quantity of products for that code. In column C i want to put the company name associated with the product and the number/quantity.
I want to know that are there anyway I can quickly declare the header row of the sheet into a string instead go through each one of them using dim xxxxx AS String?
Basically I have a string of dates, I want to get the max of the values that are before a specific date and return the header. Look at the file I provide for better understanding.
I am trying to write a macro to search a column for a specific text string which when found, will copy the whole row the string is in. Once this row has been copied, I then want the macro to activate a new sheet and search for the next available empty row to paste the data. Once this has been done, go back to the original sheet and find the next cell in the original column with the specified text string and repeat until the range has been satisfied. Below is the script I have that sort of works.
I am trying to write a formula where the column header of the row in which a value other than 0 exists, will display for each instance (row) where a value exists in an array spanning 3 columns. So the result cell could be any of the three column headers, or a combination thereof.
I started the formula in P2 of the GL Detail-2012 tab. File attached.
Here is what I started: =INDEX($M$1:$O$1,SUMPRODUCT(COUNTIF($M$2:$O$67756,))). Not working.
I would like to display the column header of the row in which a value other than 0 exists in a cell for each instance that value exists in an array spanning 3 columns. So the result cell could be any of the three column headers.
I started the formula in P2 of the GL Detail-2012 tab. (FILE TOO BIG)
I have the following sample data set and I'm trying to return the appropriate column header based on criteria (i.e. DDD) and a number value which will be somewhere within the range of the table. In example below, the value returned should be Header 2 because the value is greater than those in Header 1 column (range H9 to L26).
This works, UNLESS "My Column Header" is the last column, or second to last column, then it jumps left two columns, instead of landing on the correct column.
The purpose of this script is to select a cell directly in that column that I was searching for.
I need a formula to return column header if there is data in the column, any data.But I also need to return the second, third, fourth header with data too
In column A row 2, I have =IF(M8"",$M$1,IF(N8"",$N$1,IF(O8"",$O$1,IF(P8"",$P$1,IF(Q8"",$Q$1,IF(R8"",$R$1,IF(S8"",$S$1,IF(T8"",$T$1,""))))))))
This returns the row 1 header for the first instance of data in row 2 columns M thru T But in B2, I need the second header with data in the column.
I need the results in yellow (1st, 2nd, 3rd, 4th) from the array to it's left
1St match2nd 3rd 4thColumn MColumn NColumn OColumn PColumn QColumn R Column MColumn PColumn QData data2Data3 Column NColumn OColumn PColumn R Data Data2 data3 data4
Would use match/index but can't increment it to the second or 3rd match
I have a code that copies Sheet1 and send it via email. Everything works fine, besides that I can't get the header copied in the file that is going to be sent. I am attaching a sample workbook.
I need tweaking a new recorded macro, since it is a little bit more complex.... Basically, I want the macro to prompt open a text file then set the parameters for the text import wizard menu (which is where I am now). When it opens, the first row is blank. I want to copy another file's header (row1), lets call it PB Header.xls, to the blank row of the text file. here is the macro so far: ...
I'm looking for a formula that will return the column header (a date) of the first instance of a number greater than 0. For example if columns A through S had dates as in row 1 (header row), and in row 2, every column contained a 0 up until column P, I would want the date (Row 1, Column P) returned? I think this might be a sort of index/match formula, but I am not very familiar with these.
I have a spreadsheet with several columns (all column names are in row 1).
I have 2 of column names. Note that their actual column# might change so the macro would have to look for the column name and NOT the column position ...
Everyday I get reports on Spreadsheet1 from different users, who all keep the same format & Headers and I am trying to compile these on Spreadsheet2. So that I can copy cell data from this Spreadsheet2 to a cells in another spreadsheet3, under same headers but having more or different number of columns and also the command/action runs till the end of Row with data on Spreadsheet1 or Spreadsheet2. Ultimately I am going to append records from Spreadsheet3 onto a table in Access Database. For some reasons I have to keep the reports on Excell spreadsheet.
I want to filter my dataset, select column B & C to copy, but exclude the header row. I am having a hard time offsetting the selected range. I get a compile error on what I try.Here is my code (yes, I know, its a little juvenile and I will clean it up, but I need to see things clearer at first):
I am trying to match headers of different files and copy data.If the one of the header is not matched then a new column with the non matching header should be created and the column has to be copied
Ex: file1.xlsx has AA BB CC as header file2.xlsx has AA BB DD EE as header file3.xlsx should contain AA BB CC DD EE i.e data from file1.xlsx and file2.xlsx
I have more than 300 files how can I copy all the files to one excel file by matching headers ?
Trying to paste filtered results except header row. My code below pastes the header row for "Details" 2x. I tried altering the row to row 2, but that caused incorrect results to be returned.
Detail - Sales First I filter the data range for " Total Sales" Paste the results with header row to wsDetails
Details - Details Then filter the data again for "N" I would like to paste these results to wsDetails w/o the header
Option Explicit Sub comp_pl_ytd_Totals() Dim wbBook As Workbook Dim wsData As Worksheet Dim wsTotals As Worksheet Dim wsDetails As Worksheet Dim wsExtract As Worksheet Dim rngData As Range Dim rngCrit As Range Dim rngDest As Range Dim arrCrit Dim myRange As Range Dim C As Range Dim lngrows As Long Dim strFormula As String Dim rngCase As Range With Application . ScreenUpdating = False .DisplayAlerts = False .Calculation = xlCalculationManual End With................
The column header row for a string; if the header contains one of two possible strings then copy the entire column. I've tried the following code but it's not working.
Select Case oColHeader Case InStr(oColHeader, "how much", 1) > 0 Selection.EntireColumn.Copy Case InStr(oColHeader, "level of sat", 1) > 0 Selection.EntireColumn.Copy End Select
I would like to add the column header to each of the row item and price, we maintain masters in the matrix format, butthe application supports only the row item mapping with the customer and pricing. Attached excel file
I need a formula to lookup and retrieve data from a table of values. Given an EMP-ID in column A of the row that contains the formula and given a column name in row 1 of the column that contains the formula, I need to do a lookup. So, in effect, I am doing a lookup based on two values .. the column header and the row header.
I have attached a small model to illustrate what I need. Cell C-3 in the first worksheet will contain the formula to lookup and retrieve the value in cell C-7 in the second worksheet, based on the values in cell C-1 (column header = “Database Col 2”) and in cell A-3 (row header = “257”) in the first worksheet.
Is there a way to reference a column depending on its header? Is there a way of doing this without the need of surveying one-by-one all the column headers with a for loop? I need this cuz if I have a very dinamic program which moves columns arround and depending on the state of the program the position of a column can change.
Have a set of dates as column headers across a worksheet. Rows are product names. When a product is delivered, the cell is marked "delivered" for the date (in the column header) it was delivered. Need a formula that will look across each row (product), and return the date of the first cell with the value "delivered". I have: =INDEX(F19:AS19,1,MATCH("delivered",F19:AS19,0)) <for row 19. right now, but its just giving me "delivered" as the value and I cant figure out why.
